Optimal. Leaf size=264 \[ \frac{2 d^2 e (2 m+3 p+7) (g x)^{m+2} \left (d^2-e^2 x^2\right )^p \left (1-\frac{e^2 x^2}{d^2}\right )^{-p} \, _2F_1\left (\frac{m+2}{2},-p;\frac{m+4}{2};\frac{e^2 x^2}{d^2}\right )}{g^2 (m+2) (m+2 p+4)}-\frac{e (g x)^{m+2} \left (d^2-e^2 x^2\right )^{p+1}}{g^2 (m+2 p+4)}+\frac{2 d^3 (2 m+p+3) (g x)^{m+1} \left (d^2-e^2 x^2\right )^p \left (1-\frac{e^2 x^2}{d^2}\right )^{-p} \, _2F_1\left (\frac{m+1}{2},-p;\frac{m+3}{2};\frac{e^2 x^2}{d^2}\right )}{g (m+1) (m+2 p+3)}-\frac{3 d (g x)^{m+1} \left (d^2-e^2 x^2\right )^{p+1}}{g (m+2 p+3)} \]
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Rubi [A] time = 0.372519, antiderivative size = 264, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 4, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.148, Rules used = {1809, 808, 365, 364} \[ \frac{2 d^2 e (2 m+3 p+7) (g x)^{m+2} \left (d^2-e^2 x^2\right )^p \left (1-\frac{e^2 x^2}{d^2}\right )^{-p} \, _2F_1\left (\frac{m+2}{2},-p;\frac{m+4}{2};\frac{e^2 x^2}{d^2}\right )}{g^2 (m+2) (m+2 p+4)}-\frac{e (g x)^{m+2} \left (d^2-e^2 x^2\right )^{p+1}}{g^2 (m+2 p+4)}+\frac{2 d^3 (2 m+p+3) (g x)^{m+1} \left (d^2-e^2 x^2\right )^p \left (1-\frac{e^2 x^2}{d^2}\right )^{-p} \, _2F_1\left (\frac{m+1}{2},-p;\frac{m+3}{2};\frac{e^2 x^2}{d^2}\right )}{g (m+1) (m+2 p+3)}-\frac{3 d (g x)^{m+1} \left (d^2-e^2 x^2\right )^{p+1}}{g (m+2 p+3)} \]
Antiderivative was successfully verified.
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Rule 1809
Rule 808
Rule 365
Rule 364
Rubi steps
\begin{align*} \int (g x)^m (d+e x)^3 \left (d^2-e^2 x^2\right )^p \, dx &=-\frac{e (g x)^{2+m} \left (d^2-e^2 x^2\right )^{1+p}}{g^2 (4+m+2 p)}-\frac{\int (g x)^m \left (d^2-e^2 x^2\right )^p \left (-d^3 e^2 (4+m+2 p)-2 d^2 e^3 (7+2 m+3 p) x-3 d e^4 (4+m+2 p) x^2\right ) \, dx}{e^2 (4+m+2 p)}\\ &=-\frac{3 d (g x)^{1+m} \left (d^2-e^2 x^2\right )^{1+p}}{g (3+m+2 p)}-\frac{e (g x)^{2+m} \left (d^2-e^2 x^2\right )^{1+p}}{g^2 (4+m+2 p)}+\frac{\int (g x)^m \left (2 d^3 e^4 (3+2 m+p) (4+m+2 p)+2 d^2 e^5 (3+m+2 p) (7+2 m+3 p) x\right ) \left (d^2-e^2 x^2\right )^p \, dx}{e^4 (3+m+2 p) (4+m+2 p)}\\ &=-\frac{3 d (g x)^{1+m} \left (d^2-e^2 x^2\right )^{1+p}}{g (3+m+2 p)}-\frac{e (g x)^{2+m} \left (d^2-e^2 x^2\right )^{1+p}}{g^2 (4+m+2 p)}+\frac{\left (2 d^3 (3+2 m+p)\right ) \int (g x)^m \left (d^2-e^2 x^2\right )^p \, dx}{3+m+2 p}+\frac{\left (2 d^2 e (7+2 m+3 p)\right ) \int (g x)^{1+m} \left (d^2-e^2 x^2\right )^p \, dx}{g (4+m+2 p)}\\ &=-\frac{3 d (g x)^{1+m} \left (d^2-e^2 x^2\right )^{1+p}}{g (3+m+2 p)}-\frac{e (g x)^{2+m} \left (d^2-e^2 x^2\right )^{1+p}}{g^2 (4+m+2 p)}+\frac{\left (2 d^3 (3+2 m+p) \left (d^2-e^2 x^2\right )^p \left (1-\frac{e^2 x^2}{d^2}\right )^{-p}\right ) \int (g x)^m \left (1-\frac{e^2 x^2}{d^2}\right )^p \, dx}{3+m+2 p}+\frac{\left (2 d^2 e (7+2 m+3 p) \left (d^2-e^2 x^2\right )^p \left (1-\frac{e^2 x^2}{d^2}\right )^{-p}\right ) \int (g x)^{1+m} \left (1-\frac{e^2 x^2}{d^2}\right )^p \, dx}{g (4+m+2 p)}\\ &=-\frac{3 d (g x)^{1+m} \left (d^2-e^2 x^2\right )^{1+p}}{g (3+m+2 p)}-\frac{e (g x)^{2+m} \left (d^2-e^2 x^2\right )^{1+p}}{g^2 (4+m+2 p)}+\frac{2 d^3 (3+2 m+p) (g x)^{1+m} \left (d^2-e^2 x^2\right )^p \left (1-\frac{e^2 x^2}{d^2}\right )^{-p} \, _2F_1\left (\frac{1+m}{2},-p;\frac{3+m}{2};\frac{e^2 x^2}{d^2}\right )}{g (1+m) (3+m+2 p)}+\frac{2 d^2 e (7+2 m+3 p) (g x)^{2+m} \left (d^2-e^2 x^2\right )^p \left (1-\frac{e^2 x^2}{d^2}\right )^{-p} \, _2F_1\left (\frac{2+m}{2},-p;\frac{4+m}{2};\frac{e^2 x^2}{d^2}\right )}{g^2 (2+m) (4+m+2 p)}\\ \end{align*}
Mathematica [A] time = 0.174636, size = 194, normalized size = 0.73 \[ x (g x)^m \left (d^2-e^2 x^2\right )^p \left (1-\frac{e^2 x^2}{d^2}\right )^{-p} \left (\frac{d^3 \, _2F_1\left (\frac{m+1}{2},-p;\frac{m+3}{2};\frac{e^2 x^2}{d^2}\right )}{m+1}+e x \left (\frac{3 d^2 \, _2F_1\left (\frac{m+2}{2},-p;\frac{m+4}{2};\frac{e^2 x^2}{d^2}\right )}{m+2}+e x \left (\frac{3 d \, _2F_1\left (\frac{m+3}{2},-p;\frac{m+5}{2};\frac{e^2 x^2}{d^2}\right )}{m+3}+\frac{e x \, _2F_1\left (\frac{m+4}{2},-p;\frac{m+6}{2};\frac{e^2 x^2}{d^2}\right )}{m+4}\right )\right )\right ) \]
Antiderivative was successfully verified.
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Maple [F] time = 0.682, size = 0, normalized size = 0. \begin{align*} \int \left ( gx \right ) ^{m} \left ( ex+d \right ) ^{3} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{p}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (e x + d\right )}^{3}{\left (-e^{2} x^{2} + d^{2}\right )}^{p} \left (g x\right )^{m}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (e^{3} x^{3} + 3 \, d e^{2} x^{2} + 3 \, d^{2} e x + d^{3}\right )}{\left (-e^{2} x^{2} + d^{2}\right )}^{p} \left (g x\right )^{m}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [C] time = 61.7982, size = 262, normalized size = 0.99 \begin{align*} \frac{d^{3} d^{2 p} g^{m} x x^{m} \Gamma \left (\frac{m}{2} + \frac{1}{2}\right ){{}_{2}F_{1}\left (\begin{matrix} - p, \frac{m}{2} + \frac{1}{2} \\ \frac{m}{2} + \frac{3}{2} \end{matrix}\middle |{\frac{e^{2} x^{2} e^{2 i \pi }}{d^{2}}} \right )}}{2 \Gamma \left (\frac{m}{2} + \frac{3}{2}\right )} + \frac{3 d^{2} d^{2 p} e g^{m} x^{2} x^{m} \Gamma \left (\frac{m}{2} + 1\right ){{}_{2}F_{1}\left (\begin{matrix} - p, \frac{m}{2} + 1 \\ \frac{m}{2} + 2 \end{matrix}\middle |{\frac{e^{2} x^{2} e^{2 i \pi }}{d^{2}}} \right )}}{2 \Gamma \left (\frac{m}{2} + 2\right )} + \frac{3 d d^{2 p} e^{2} g^{m} x^{3} x^{m} \Gamma \left (\frac{m}{2} + \frac{3}{2}\right ){{}_{2}F_{1}\left (\begin{matrix} - p, \frac{m}{2} + \frac{3}{2} \\ \frac{m}{2} + \frac{5}{2} \end{matrix}\middle |{\frac{e^{2} x^{2} e^{2 i \pi }}{d^{2}}} \right )}}{2 \Gamma \left (\frac{m}{2} + \frac{5}{2}\right )} + \frac{d^{2 p} e^{3} g^{m} x^{4} x^{m} \Gamma \left (\frac{m}{2} + 2\right ){{}_{2}F_{1}\left (\begin{matrix} - p, \frac{m}{2} + 2 \\ \frac{m}{2} + 3 \end{matrix}\middle |{\frac{e^{2} x^{2} e^{2 i \pi }}{d^{2}}} \right )}}{2 \Gamma \left (\frac{m}{2} + 3\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (e x + d\right )}^{3}{\left (-e^{2} x^{2} + d^{2}\right )}^{p} \left (g x\right )^{m}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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